"කැල්සියම් කාබනේට්" හි සංශෝධන අතර වෙනස්කම්

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==ද්‍රාව්‍යතාව==
==Solubility==
===With varying CO<sub>2</sub> pressure===
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Calciumකැල්සියම් carbonateකාබනේට් is poorly soluble in pure water (47&nbsp;mg/L at normal atmospheric CO<sub>2</sub> partial pressure as shown below).
 
The equilibrium of its solution is given by the equation (with dissolved calciumකැල්සියම් carbonateකාබනේට් on the right):
:{| width="450"
| width="50%" height="30"| CaCO<sub>3</sub> {{eqm}} Ca<sup>2+</sup> + CO<sub>3</sub><sup>2–</sup>
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HCO<sub>3</sub><sup>–</sup> is known as the [[bicarbonate]] ion. [[Calcium bicarbonate]] is many times more soluble in water than calciumකැල්සියම් carbonate—indeedකාබනේට්—indeed it exists ''only'' in solution.
 
Some of the HCO<sub>3</sub><sup>–</sup> combines with H<sup>+</sup> in solution according to:
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:2[Ca<sup>2+</sup>] + [H<sup>+</sup>] = [HCO<sub>3</sub><sup>–</sup>] + 2[CO<sub>3</sub><sup>2–</sup>] + [OH<sup>–</sup>]
 
make it possible to solve simultaneously for the remaining five unknown concentrations (note that the above form of the neutrality equation is valid only if calciumකැල්සියම් carbonateකාබනේට් has been put in contact with pure water or with a neutral pH solution; in the case where the origin water solvent pH is not neutral, the equation is modified).
 
[[Image:CanarySpring.jpg|thumb|right|Travertine calciumකැල්සියම් carbonateකාබනේට් deposits from a [[hot spring]]]]
 
The table on the right shows the result for [Ca<sup>2+</sup>] and [H<sup>+</sup>] (in the form of pH) as a function of ambient partial pressure of CO<sub>2</sub> (''K''<sub>sp</sub> = 4.47×10<sup>−9</sup> has been taken for the calculation).
267 පේළිය:
*As ambient CO<sub>2</sub> partial pressure increases to levels above atmospheric, pH drops, and much of the carbonate ion is converted to bicarbonate ion, which results in higher solubility of Ca<sup>2+</sup>.
 
The effect of the latter is especially evident in day to day life of people who have hard water. Water in aquifers underground can be exposed to levels of CO<sub>2</sub> much higher than atmospheric. As such water percolates through calciumකැල්සියම් carbonateකාබනේට් rock, the CaCO<sub>3</sub> dissolves according to the second trend. When that same water then emerges from the tap, in time it comes into equilibrium with CO<sub>2</sub> levels in the air by outgassing its excess CO<sub>2</sub>. The calciumකැල්සියම් carbonateකාබනේට් becomes less soluble as a result and the excess precipitates as lime scale. This same process is responsible for the formation of [[stalactites]] and [[stalagmite]]s in limestone caves.
 
Two hydrated phases of calciumකැල්සියම් carbonateකාබනේට්, [[monohydrocalcite]], CaCO<sub>3</sub>·H<sub>2</sub>O and [[ikaite]], CaCO<sub>3</sub>·6H<sub>2</sub>O, may [[precipitate]] from water at ambient conditions and persist as metastable phases.
 
===With varying pH===
We now consider the problem of the maximum solubility of calciumකැල්සියම් carbonateකාබනේට් in normal atmospheric conditions (<math>\scriptstyle P_{\mathrm{CO}_2}</math> = 3.5 × 10<sup>−4</sup> atm) when the pH of the solution is adjusted. This is for example the case in a swimming pool where the pH is maintained between 7 and 8 (by addition of [[sodium bisulfate]] NaHSO<sub>4</sub> to decrease the pH or of [[sodium bicarbonate]] NaHCO<sub>3</sub> to increase it). From the above equations for the solubility product, the hydration reaction and the two acid reactions, the following expression for the maximum [Ca<sup>2+</sup>] can be easily deduced:
:<math>[\text{Ca}^{2+}]_\text{max} = \frac{K_\text{sp}} {K_\text{h}K_\text{a1}K_\text{a2}k_\text{H}} \frac{[\text{H}^+]^2}{P_{\text{CO}_2}}</math>
showing a quadratic dependence in [H<sup>+</sup>]. The numerical application with the above values of the constants gives{{Citation needed|date=September 2009}}
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|49.5||4.99||0.513||0.0848||0.0504||0.0474||0.0471||0.0470||0.0470
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We see that for the same total acid concentration, the initial pH of the weak acid is less acid than the one of the strong acid; however, the maximum amount of CaCO<sub>3</sub> which can be dissolved is approximately the same. This is because in the final state, the pH is larger than the p''K''<sub>A</sub>, so that the weak acid is almost completely dissociated, yielding in the end as many H<sup>+</sup> ions as the strong acid to "dissolve" the calciumකැල්සියම් carbonateකාබනේට්.
 
*The calculation in the case of [[phosphoric acid]] (which is the most widely used for domestic applications) is more complicated since the concentrations of the four dissociation states corresponding to this acid must be calculated together with [HCO<sub>3</sub><sup>-</sup>], [CO<sub>3</sub><sup>2-</sup>], [Ca<sup>2+</sup>], [H<sup>+</sup>] and [OH<sup>-</sup>]. The system may be reduced to a seventh degree equation for [H<sup>+</sup>] the numerical solution of which gives
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