"කැල්සියම් කාබනේට්" හි සංශෝධන අතර වෙනස්කම්
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174 පේළිය:
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==ද්රාව්යතාව==
===With varying CO<sub>2</sub> pressure===
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206 පේළිය:
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The equilibrium of its solution is given by the equation (with dissolved
:{| width="450"
| width="50%" height="30"| CaCO<sub>3</sub> {{eqm}} Ca<sup>2+</sup> + CO<sub>3</sub><sup>2–</sup>
221 පේළිය:
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HCO<sub>3</sub><sup>–</sup> is known as the [[bicarbonate]] ion. [[Calcium bicarbonate]] is many times more soluble in water than
Some of the HCO<sub>3</sub><sup>–</sup> combines with H<sup>+</sup> in solution according to:
255 පේළිය:
:2[Ca<sup>2+</sup>] + [H<sup>+</sup>] = [HCO<sub>3</sub><sup>–</sup>] + 2[CO<sub>3</sub><sup>2–</sup>] + [OH<sup>–</sup>]
make it possible to solve simultaneously for the remaining five unknown concentrations (note that the above form of the neutrality equation is valid only if
[[Image:CanarySpring.jpg|thumb|right|Travertine
The table on the right shows the result for [Ca<sup>2+</sup>] and [H<sup>+</sup>] (in the form of pH) as a function of ambient partial pressure of CO<sub>2</sub> (''K''<sub>sp</sub> = 4.47×10<sup>−9</sup> has been taken for the calculation).
267 පේළිය:
*As ambient CO<sub>2</sub> partial pressure increases to levels above atmospheric, pH drops, and much of the carbonate ion is converted to bicarbonate ion, which results in higher solubility of Ca<sup>2+</sup>.
The effect of the latter is especially evident in day to day life of people who have hard water. Water in aquifers underground can be exposed to levels of CO<sub>2</sub> much higher than atmospheric. As such water percolates through
Two hydrated phases of
===With varying pH===
We now consider the problem of the maximum solubility of
:<math>[\text{Ca}^{2+}]_\text{max} = \frac{K_\text{sp}} {K_\text{h}K_\text{a1}K_\text{a2}k_\text{H}} \frac{[\text{H}^+]^2}{P_{\text{CO}_2}}</math>
showing a quadratic dependence in [H<sup>+</sup>]. The numerical application with the above values of the constants gives{{Citation needed|date=September 2009}}
369 පේළිය:
|49.5||4.99||0.513||0.0848||0.0504||0.0474||0.0471||0.0470||0.0470
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We see that for the same total acid concentration, the initial pH of the weak acid is less acid than the one of the strong acid; however, the maximum amount of CaCO<sub>3</sub> which can be dissolved is approximately the same. This is because in the final state, the pH is larger than the p''K''<sub>A</sub>, so that the weak acid is almost completely dissociated, yielding in the end as many H<sup>+</sup> ions as the strong acid to "dissolve" the
*The calculation in the case of [[phosphoric acid]] (which is the most widely used for domestic applications) is more complicated since the concentrations of the four dissociation states corresponding to this acid must be calculated together with [HCO<sub>3</sub><sup>-</sup>], [CO<sub>3</sub><sup>2-</sup>], [Ca<sup>2+</sup>], [H<sup>+</sup>] and [OH<sup>-</sup>]. The system may be reduced to a seventh degree equation for [H<sup>+</sup>] the numerical solution of which gives
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